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The area of a rectangle is 130 mm². The length is 3 mm greater than its width. Let x represent the width of the rectangle.
Which equation can be used to solve for x?
O A. 3x = 130
O B. x2 + 3 = 130
C. x(x + 3) = 130
D. (x+3)2 = 130


The Area Of A Rectangle Is 130 Mm The Length Is 3 Mm Greater Than Its Width Let X Represent The Width Of The Rectangle Which Equation Can Be Used To Solve For X class=

Sagot :

Answer:

L = 3 + x

W = x

A = L x W

130 = 3 +( x × x)

B. X2 + 3 = 130

The equation that can be used to solve for x is;

x(x + 3) = 130

Area of a Rectangle

We are told that area of a rectangle is;

A = 130 mm².

We are told that length is 3 mm greater than its width.

Now, if the width is x, then

Length = x + 3

Formula for area of a rectangle is;

A = length * width

Thus;

(x + 3)x = 130

x² + 3x = 130

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