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what is the pH of a 2.58 x 10^-6 M solution of an acid?

Sagot :

Stephen46idn

Answer:

5.59

Explanation:

The pH of a solution can be found by using the formula

[tex]pH = - log [ {H}^{+} ][/tex]

From the question we have

[tex]ph = - log(2.58 \times {10}^{ - 6} ) \\ = 5.58838[/tex]

We have the final answer as

5.59

Hope this helps you

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