Xtrashykfvidn
Answered

Expand your horizons with the diverse and informative answers found on IDNLearn.com. Get accurate and detailed answers to your questions from our dedicated community members who are always ready to help.

ok LAST ONE I PRIMKSE

Ok LAST ONE I PRIMKSE class=

Sagot :

Answer:  y = 9sqrt(3)

"sqrt" is shorthand for "square root". If you need x as well, it is x = 18

=============================================================

Explanation:

This is a 30-60-90 triangle. The hypotenuse is twice that of the short leg, so the hypotenuse is x = 2*9 = 18 units.

The long leg is sqrt(3) times the short leg, so y = 9sqrt(3)

You could use the trig ratios (sine, cosine, tangent) to help find these values.

Spaceidn

Answer:

[tex]\displaystyle y = 9\sqrt{3}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

Trigonometry

  • [Right Triangles Only] SOHCAHTOA
  • [Right Triangles Only] tanθ = opposite over adjacent

Step-by-step explanation:

Step 1: Define

Identify variables

Angle θ = 30°

Opposite Leg = 9

Adjacent Leg = y

Step 2: Solve for y

  1. Substitute in variables [Tangent]:                                                                    [tex]\displaystyle tan(30^\circ) = \frac{9}{y}[/tex]
  2. [Multiplication Property of Equality] Cross-multiply:                                        [tex]\displaystyle y = \frac{9}{tan(30^\circ)}[/tex]
  3. Evaluate:                                                                                                           [tex]\displaystyle y = 9\sqrt{3}[/tex]
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Find reliable answers at IDNLearn.com. Thanks for stopping by, and come back for more trustworthy solutions.