IDNLearn.com: Your one-stop destination for reliable answers to diverse questions. Join our interactive Q&A platform to receive prompt and accurate responses from experienced professionals in various fields.
Sagot :
Answer: The half-reactions represents reduction are as follows.
- [tex]Cr_{2}O^{2-}_{7} \rightarrow Cr^{3+}[/tex]
- [tex]MnO^{-}_{4} \rightarrow Mn^{2+}[/tex]
Explanation:
A half-reaction where addition of electrons take place or a reaction where decrease in oxidation state of an element takes place is called reduction-half reaction.
For example, the oxidation state of Cr in [tex]Cr_{2}O^{2-}_{7}[/tex] is +6 which is getting converted into +3, that is, decrease in oxidation state is taking place as follows.
[tex]Cr_{2}O^{2-}_{7} + 3 e^{-} \rightarrow Cr^{3+}[/tex]
Similarly, oxidation state of Mn in [tex]MnO^{-}_{4}[/tex] is +7 which is getting converted into +2, that is, decrease in oxidation state is taking place as follows.
[tex]MnO^{2-}_{4} + 5 e^{-} \rightarrow Mn^{2+}[/tex]
Thus, we can conclude that half-reactions represents reduction are as follows.
- [tex]Cr_{2}O^{2-}_{7} \rightarrow Cr^{3+}[/tex]
- [tex]MnO^{-}_{4} \rightarrow Mn^{2+}[/tex]
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Discover the answers you need at IDNLearn.com. Thanks for visiting, and come back soon for more valuable insights.
