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Which of these half-reactions represents reduction?
I. Fe2+ → Fe3+
II. Cr2O72- → Cr3+
III. MnO4- → Mn2+


Sagot :

Answer: The half-reactions represents reduction are as follows.

  • [tex]Cr_{2}O^{2-}_{7} \rightarrow Cr^{3+}[/tex]
  • [tex]MnO^{-}_{4} \rightarrow Mn^{2+}[/tex]

Explanation:

A half-reaction where addition of electrons take place or a reaction where decrease in oxidation state of an element  takes place is called reduction-half reaction.

For example, the oxidation state of Cr in [tex]Cr_{2}O^{2-}_{7}[/tex] is +6 which is getting converted into +3, that is, decrease in oxidation state is taking place as follows.

[tex]Cr_{2}O^{2-}_{7} + 3 e^{-} \rightarrow Cr^{3+}[/tex]

Similarly, oxidation state of Mn in [tex]MnO^{-}_{4}[/tex] is +7 which is getting converted into +2, that is, decrease in oxidation state is taking place as follows.

[tex]MnO^{2-}_{4} + 5 e^{-} \rightarrow Mn^{2+}[/tex]

Thus, we can conclude that half-reactions represents reduction are as follows.

  • [tex]Cr_{2}O^{2-}_{7} \rightarrow Cr^{3+}[/tex]
  • [tex]MnO^{-}_{4} \rightarrow Mn^{2+}[/tex]
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