Answered

Discover how IDNLearn.com can help you find the answers you need quickly and easily. Our platform provides trustworthy answers to help you make informed decisions quickly and easily.

Word problem in Algebra - Two boys, Shawn and Curtis, went for a walk, Shawn began walking 20 seconds earlier than Curtis. Shawn walked at a speed of 5 feet per second. Curtis walked at a speed of 6 feet per second. For How many seconds had Shawn been walking at the moment when the two boys had walked the same distance?



Sagot :

TclmcMKidn
So first you should simplify it.
Shawn (S) - 5 ft. per sec
Curtis (C) - 6 ft. per sec
     1 sec        2 s         3 s         4s        5s          6s
S     25 ft       30 ft       35 ft      40 ft      45 ft      50 ft
C     6 ft        12 ft       18 ft      24 ft      30 ft      36 ft
So we keep going on with this table until we find two numbers that match, which is 30. Then we look back at the question. We want to find how many seconds Shawn was at when the hit the same distance as Curtis (30 ft). Yet be sure to keep in mind that Shawn started 20 seconds earlier. So the answer is 2 seconds.
Thank you for participating in our discussion. We value every contribution. Keep sharing knowledge and helping others find the answers they need. Let's create a dynamic and informative learning environment together. IDNLearn.com provides the best answers to your questions. Thank you for visiting, and come back soon for more helpful information.