Answered

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REALIZAR LA MASA MOLECULAR DE LOS SIGUIENTES COMPUESTOS HIDROXIDO DE MAGNESIO = Mg(OH)2 ACIDO CARBONICO = H2CO3 GLUCOSA= C6H12O6

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Answer:

Mg(OH)2 = 58.321g/mol

H2CO3 = 62.026g/mol

C6H12O6 = 180.156g/mol

Explanation:

Para hallar la masa molecular debemos, primero, identificar las moles de cada átomo presentes en una mol de una molécula. Por ejemplo, para el hidróxido de magnesio:

Mg = 1mol

O = 2mol

H = 2mol

Ahora, debemos hacer la suma del peso molecular de todos estos átomos. Esto es:

Mg = 1mol * (24.305g/mol) = 24.305g/mol

O = 2mol * (16g/mol) = 32g/mol

H = 2mol* (1.008g/mol) = 2.016g/mol

El peso molecular del hidróxido de magnesio es:

24.305g/mol + 32g/mol + 2.016g/mol = 58.321g/mol

Ácido Carbónico:

H = 2mol * (1.008g/mol) = 2.016g/mol

C = 1mol * (12.01g/mol) = 12.01g/mol

O = 3mol * (16g/mol) = 48g/mol

Masa molar = 62.026g/mol

Glucosa:

C = 6mol * (12.01g/mol) = 72.06g/mol

H = 12mol * (1.008g/mol) = 12.096g/mol

O = 6mol * (16g/mol) = 96g/mol

Masa molar = 180.156g/mol

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