Answered

Find answers to your questions and expand your knowledge with IDNLearn.com. Our community is ready to provide in-depth answers and practical solutions to any questions you may have.

If a fisherman applies a horizontal force with magnitude 47.0 NN to the box and produces an acceleration of magnitude 3.20 m/s2m/s2, what is the mass of the box

Sagot :

Cricetusidn

Answer:

The correct solution is "14.6875 kg".

Explanation:

Given values:

Force,

F = 47.0 N

Acceleration,

a = 3.20 m/s²

Now,

⇒ [tex]Force=Mass\times Acceleration[/tex]

or,

⇒       [tex]F=ma[/tex]

⇒    [tex]47.0=m\times 3.20[/tex]

⇒       [tex]m=\frac{47.0}{3.20}[/tex]

⇒           [tex]=14.6875 \ kg[/tex]

Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. Thank you for trusting IDNLearn.com with your questions. Visit us again for clear, concise, and accurate answers.