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-2x^3(3x^2-4x+7)
?????

Sagot :

Doomdabombidn

Answer:

[tex]-6x^5+8x^4-14x^3[/tex]

Step-by-step explanation:

[tex]-2x^3(3x^2-4x+7)[/tex]   Use distributive property

[tex]-2x^3[/tex] · [tex]3x^2[/tex] = [tex]-6x^5[/tex]      

[tex]-2x^3[/tex] · [tex]-4x[/tex] = [tex]8x^4[/tex]       Product becomes positive because of two negatives

[tex]-2x^3[/tex] · [tex]7[/tex] = [tex]-14x^3[/tex]

Group all of those numbers together (in order)

[tex]-6x^5+8x^4-14x^3[/tex]
its -2^3*(-5^2x+7) and 5^3x-14^3
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