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A 400-gram sample of iron, initially at 21 0Cis heated to 65 0C. Determine the energy attained (in Joules) by the iron sample if the specific heat capacity of iron is 0.11 cal/g0C

Sagot :

Sebassandinidn

Answer:

Q = 8100 J.

Explanation:

Hello there!

In this case, according to the given information, we can infer this is a question about calorimetry, and we can use the general heat equation to solve this one:

[tex]Q=mC(T_2-T_1)[/tex]

Thus, we plug in the given mass, specific heat and temperatures to obtain the energy involved in this heating process:

[tex]Q=400g*0.11\frac{cal}{g\°C} (65\°C-21\°C)\\\\Q=1936cal[/tex]

Which converted to Joules turns out to be:

[tex]Q=1936cal*\frac{4.184J}{1cal} \\\\Q=8100J[/tex]

Regards!

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