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200 grams of iron (III) chloride reacts with ammonium carbonate [(NH4)2CO3] in the following equation.

FeCl3 + (NH4)2CO3 ---------> NH4Cl + Fe2(CO3)3



The number of grams of ammonium chloride (NH4Cl) that will be produced is ___ grams.


a
395
b
181
c
198
d
339

Sagot :

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Answer:

[tex]FeCl₃ + (NH₄)₂CO₃ → NH₄Cl + Fe₂(CO₃)₃[/tex]

first balance the chemical equation

first balance the chemical equation[tex]2FeCl₃ + 3(NH₄)₂CO₃ → 6NH₄Cl + Fe₂(CO₃)₃[/tex]

2FeCl₃=2*162=324g

6NH₄Cl=6*53.5=321g

324 g of FeCl₃ gives 321 g of NH₄Cl

200g of FeCl₃ gives 321/324*200=198.14 g of NH₄Cl

in nearest value it is 198g/mole

The number of grams of ammonium chloride (NH4Cl) that will be produced is C.198___ grams.

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