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Sagot :
Answer:
0.616 moles of Fe₂(CO₃)₃ are produced when 200 g of FeCl₃ react
b. 1.
Explanation:
The balanced reaction is:
- 2FeCl₃ + 3(NH₄)₂CO₃ → 6NH₄Cl + Fe₂(CO₃)₃
First we convert 200 grams of FeCl₃ into moles, using its molar mass:
- 200 g ÷ 162.2 g/mol = 1.23 mol FeCl₃
Then we convert 1.23 moles of FeCl₃ into moles of Fe₂(CO₃)₃, using the stoichiometric coefficients of the balanced reaction:
- 1.23 mol FeCl₃ * [tex]\frac{1molFe_2(CO_3)_3}{2molFeCl_3}[/tex] = 0.616 mol Fe₂(CO₃)₃
The closest answer would be option b. 1.
Explanation:
[tex]FeCl₃ + (NH₄)₂CO₃ → NH₄Cl + Fe₂(CO₃)₃[/tex]
first balance the chemical equation
[tex]2FeCl₃ + 3(NH₄)₂CO₃ → 6NH₄Cl + Fe₂(CO₃)₃[/tex]
2 mole. 3 mole. 6mole. 1mole
2*162g of FeCl₃ produce 236 g of Fe₂(CO₃)₃
200g of of FeCl₃
produce 236/(2*162)*20=145.68 g of Fe₂(CO₃)₃
1 mole of Fe₂(CO₃)₃=236g
145.68g of Fe₂(CO₃)=1/236*145.68=}0.61mole
closest answer is b 1
b.1mole(s) of iron (III) carbonate [Fe2CO3)3] is/are produced in the balanced equation
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