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Express the confidence interval (63.3%, 79.1%) in the form of ˆp ± ME.
___% ± ___%

Sagot :

MrRoyalidn

Answer:

[tex]p \± ME[/tex] [tex]\to[/tex] [tex]71.2\% \± 7.9\%[/tex]

Step-by-step explanation:

Given

[tex](63.3\%,79.1\%)[/tex]

Required

Express in form of: [tex]p \± ME[/tex]

First, calculate the midpiont (p)

[tex]p = \frac{63.3\% + 79.1\%}{2}[/tex]

[tex]p = \frac{142.4\%}{2}[/tex]

[tex]p = 71.2\%[/tex]

The margin of error (ME) is:

[tex]ME =79.1\% - 71.2\%[/tex]

[tex]ME =7.9\%[/tex]

So, we have:

[tex]p \± ME[/tex] [tex]\to[/tex] [tex]71.2\% \± 7.9\%[/tex]

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