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A 330.-ohm resistor is connected to a 5.00-volt battery. What is the current through the resistor?

Sagot :

Spectrojamzidn

Answer:

From Ohms Law

V=IR

V=5volts

R=33.0hms

I=V/R

I= 5/330

=0.0152A

Nuhulawal20idn

The current flowing through the cross-section of the resistor is 0.0152A.

Given the data in the question;

  • Resistance; [tex]R = 330ohm[/tex]
  • Voltage; [tex]V = 5.00V[/tex]
  • Current; [tex]I = \ ?[/tex]

Ohm's law

Ohm's law states that "the current flowing through the cross-section of a conductor is directly proportional to the voltage across it".

It is expressed as;

[tex]V = IR[/tex]

Where V is voltage, I is current and R is the Resistance.

To determine the current flowing through the resistor, we substitute our given values into the expression above.

[tex]V = IR\\\\I = \frac{V}{R}\\ \\I = \frac{5.00V}{330\ Ohm} \\\\I = 0.0152A[/tex]

Therefore, the current flowing through the cross-section of the resistor is 0.0152A.

Learn more about Electric current here: https://brainly.com/question/2264542

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