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the system of equations kx-5y = 2, 6x+2y = 7 has no solution, then k =

(a) -10 (b) -5 (c) -6 (d) -15​

Sagot :

Hrishiiidn

Answer:

(d) -15

Step-by-step explanation:

Given system of equations are:

[tex] \begin{cases}kx-5y=2\\\\6x+2y=7\end{cases}[/tex]

Since, given system of equations have no solution.

[tex] \therefore \frac{k}{6}=\frac{-5}{2} \neq\frac{2}{7}[/tex]

[tex] \implies \frac{k}{6}=\frac{-5}{2} [/tex]

[tex] \implies k=\frac{6(-5)}{2} [/tex]

[tex] \implies k=\frac{-30}{2} [/tex]

[tex] \implies k=-15[/tex]

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