AbuShuraiheartidn
Answered

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Calculate the volume occupied
at s.t.p by 6.89
gas [H = 10, N = 14​

Sagot :

Dsdrajlinidn

Answer:

9.07 L

Explanation:

Calculate the volume occupied at s.t.p by 6.89 g of NH₃ gas [H = 1.0, N = 14.0​].

Step 1: Given and required data

  • Mass of NH₃ (m): 6.89 g
  • Molar mass of NH₃ (M): 17.0 g/mol

Step 2: Calculate the moles (n) of NH₃

We will use the following epxression.

n = m / M

n = 6.89 g / (17.0 g/mol) = 0.405 mol

Step 3: Calculate the volume occupied by 0.405 moles of NH₃ at STP

At STP, 1 mole of NH₃ occupies 22.4 L (assuming ideal behavior).

0.405 mol × 22.4 L/1 mol = 9.07 L

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