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How many gallons of a 80​% antifreeze solution must be mixed with 100 gallons of 20​% antifreeze to get a mixture that is 70​% antifreeze? Use the​ six-step method.

Sagot :

To Find :

How many gallons of a 80​% antifreeze solution must be mixed with 100 gallons of 20​% antifreeze to get a mixture that is 70​% antifreeze.

Solution :

Let, x gallons of 80​% antifreeze solution is required :

So,

[tex](x \times 80) + ( 100 \times 20 ) = (x + 100 )\times 70\\\\8x + 200 = 7( x + 100)\\\\x = 500[/tex]

Therefore, 500 gallons of 80% antifreeze solution is required.

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