Answered

IDNLearn.com offers expert insights and community wisdom to answer your queries. Get prompt and accurate answers to your questions from our community of experts who are always ready to help.

Demand per hour for gasoline at a local station is normally distributed with a mean of 1510 gallons and std deviation of 57 gallons. What is the probability that demand for a particular hour is greater than 1600 gallons? Enter your answer as a decimal, rounded to 4 decimal places

Sagot :

Fichohidn

Answer:

0.057168

Step-by-step explanation:

Given :

Mean = 1510

Standard deviation = 57

P(X > 1600)

To obtain the Zscore we use

(x - mean) / σ

P(Z > 1600) = P(Z > (x - mean) / σ)

P(Z > (x - mean) / σ) = P(Z > (1600 - 1510) / 57)

P(Z > 1.579) = 0.057168 (Z probability calculator)

Your presence in our community is highly appreciated. Keep sharing your insights and solutions. Together, we can build a rich and valuable knowledge resource for everyone. For precise answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.