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A zoo is creating a new exhibit that includes an aquarium in the shape of a right rectangular prism. The water level of the aquarium is 2/3 the height of the aquarium as shown. How much space, in cubic feet, in the aquarium does not contain water?

Sagot :

MrRoyalidn

Answer:

[tex]Volume=56\frac{1}{4}[/tex] cubic feet

Step-by-step explanation:

Given

[tex]L =3\frac{3}{8}ft[/tex] --- Length

[tex]W =13\frac{1}{3}ft[/tex] --- Width

[tex]H =3\frac{3}{4}[/tex] --- Tank

[tex]Water\ level = \frac{2}{3}[/tex]

Required

Space not covered with water

If the water level is:

[tex]Water\ level = \frac{2}{3}[/tex]

Then the empty space is:

[tex]Empty = 1 - Water\ level[/tex] --- Complement rule

[tex]Empty = 1 - \frac{2}{3}[/tex]

Take LCM

[tex]Empty = \frac{3-2}{3}[/tex]

[tex]Empty = \frac{1}{3}[/tex]

So, the volume of the empty space is:

[tex]Volume=L*W*H*Empty[/tex]

[tex]Volume=3\frac{3}{8} *13\frac{1}{3}*3\frac{3}{4}*\frac{1}{3}[/tex]

Express fraction as improper fraction

[tex]Volume=\frac{27}{8} *\frac{40}{3}*\frac{15}{4}*\frac{1}{3}[/tex]

Simplify

[tex]Volume=\frac{9}{8} *\frac{40}{3}*\frac{15}{4}[/tex]

Simplify

[tex]Volume=\frac{3}{8} *\frac{40}{1}*\frac{15}{4}[/tex]

Simplify

[tex]Volume=\frac{3}{1} *\frac{5}{1}*\frac{15}{4}[/tex]

[tex]Volume=\frac{3*5*15}{4}[/tex]

[tex]Volume=\frac{225}{4}[/tex]

[tex]Volume=56\frac{1}{4}[/tex]

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