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What is the equation of the line that passes through the points (4,-1 ) and (-7,4 )?

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Answer:

[tex] \large{ \tt{❃ \: STEP- BY - STEP \: EXPLANATION}} : [/tex]

  • Let the equation of line passes through the points A ( 4 , - 1 ) and B ( - 7 , 4 ) . Let A ( 4 , -1 ) be ( x₁ , y₁ ) & B ( - 7 , 4 ) be ( x₂ , y₂ )

[tex] \large{ \tt{❁ \: LET'S \: START}} : [/tex]

  • Using two - point form of the equation of straight line , we have :

[tex] \boxed{ \large{ \bf{❀ \: y -y _{1} = \frac{y_{2} - y_{1} }{x_{2} - x_{1}} (x - x_{1)}}}}[/tex]

- Plug the values :

[tex] \large{ \bf{⇢ \: y - ( - 1) = \frac{4 - ( - 1)}{ - 7 - 4}(x - 4) }}[/tex]

[tex] \large{ \bf{⇢y + 1 = \frac{4 + 1}{ - 11} (x - 4)}}[/tex]

[tex] \large{ \bf{⇢ \: y + 1 = - \frac{5}{11} (x - 4)}}[/tex]

[tex] \large{ \bf{⇢y + 1 = - \frac{5}{11}x + \frac{20}{11} }}[/tex]

[tex] \large{ \bf{⇢y + 1 = \frac{ - 5x + 20}{11} }}[/tex]

[tex] \large{ \bf{⇢11(y + 1) = - 5x + 20}}[/tex]

[tex] \large{ \bf{⇢11y + 11 = - 5x + 20}}[/tex]

[tex] \large{ \bf{⇢5x + 11y + 11 - 20 = 0}}[/tex]

[tex] ⇢ \boxed{\large{ \bold{\bf{5x + 11y - 9 = 0}}}}[/tex]

  • ♕ Hence , 5x + 11y - 9 = 0 is the required equation of the line.

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