Answered

Discover a wealth of knowledge and get your questions answered at IDNLearn.com. Ask your questions and receive reliable, detailed answers from our dedicated community of experts.

How many moles would be in 85.OmL of 0.750M KOH?

Sagot :

Answer: There are 0.0637 moles present in 85.0 mL of 0.750 M KOH.

Explanation:

Given: Volume = 85.0 mL (1 mL = 0.001 L) = 0.085 L

Molarity = 0.750 M

It is known that molarity is the number of moles of solute present in liter of a solution.

Therefore, moles present in given solution are calculated as follows.

[tex]Molarity = \frac{moles}{Volume (in L)}\\0.750 M = \frac{moles}{0.085 L}\\moles = 0.0637 mol[/tex]

Thus, we can conclude that there are 0.0637 moles present in 85.0 mL of 0.750 M KOH.

We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Find clear and concise answers at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.