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a street light is mounted at the top of a 15-foot pole. A 6-foot tall man walks away from the pole along a straight path. How long is his shadow when he is 40 feet from the pole

Sagot :

Okpalawalter8idn

Answer:

[tex]x=26.67[/tex]

Step-by-step explanation:

From the question we are told that:

Height of Pole [tex]h_p=15 foot[/tex]

Height of Man [tex]h_m =6ft[/tex]

Distance from Pole [tex]d_p=40ft[/tex]

Generally the equation for similar Property is mathematically given by

[tex]\frac{h_p}{h_m}=\frac{d_p+x}{x}[/tex]

[tex]x=\frac{h_m*(d_p+x)}{h_p}[/tex]

[tex]x=\frac{6*(40+x)}{15}[/tex]

[tex]x=\frac{240+6x}{15}[/tex]

[tex]x=16+0.4x\\x-0.4x=16[/tex]

[tex]x=16\0.6[/tex]

[tex]x=26.67[/tex]

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