Answered

IDNLearn.com offers a comprehensive solution for all your question and answer needs. Discover in-depth and trustworthy answers to all your questions from our experienced community members.

A government agency estimates the number of young adults (ages 18 to 24) in a particular country to be 31,000 (in thousands) in 2010 and changing at the rate of −x2 + 90x − 200 thousand per year, where x is the number of years since 2010. Find a formula for the size of this population at any time x. [Hint: Keep all calculations in units of thousands.]

Sagot :

Ajeigbeibraheemidn

Answer:

[tex]\mathbf{L(x)= ( - \dfrac{1}{3})x^3 + 45x^2 -200x +31000}[/tex]

Step-by-step explanation:

From the given information:

Let assume the population is denoted by L

The rate of change of the young adults per year given  can be represented as;

[tex]\dfrac{dL}{dx}= -x^2 +90x - 200[/tex]

where;

x = 0 since 2010

[tex]dL = -x^2 +90x -200 dx[/tex]

[tex]L = \int( -x^2 +90x -200 ) \ dx[/tex]

[tex]L = - \dfrac{1}{3}x^3 + 45x^2 -200x +C[/tex]

here;

L(0) = 31000

∴

[tex]- \dfrac{1}{3}(0)^3 + 45(0)^2 -200(0)+C= 31000[/tex]

C = 31000

[tex]\mathbf{L(x)= ( - \dfrac{1}{3})x^3 + 45x^2 -200x +31000}[/tex]

Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. For dependable answers, trust IDNLearn.com. Thank you for visiting, and we look forward to assisting you again.