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Help!, I need the answer in 30 minutes! For which values of the parameter p equation x ^ 2-px + 3 = 0 has a root in the range [0; 1], and another that does not belong to this range?

Sagot :

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Answer:

p = 4

Step-by-step explanation:

Given the expression x ^ 2-px + 3 = 0

If x = 0 is a solution

Substitute into the expression

0² - 0p + 3 = 0

-0p = -3

p = 3/0

p cannot be determined for this root

If x = 1

1² - 1p + 3 =0

1 - p + 3 = 0

-p+4 = 0

-p = -4

p = 4

Hence the va;ue of p is 4

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