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If h(x) = 6 – X, what is the value of (hon (10)? O 4 -2 10 If p(x) = 2x2 - 4x and q(x) = x - 3, what is (pºq)(x)? O 2x2 - 4x + 12 O 2x2 – 16x + 18 O 2x2 – 16x + 30 O 2x2 – 16x + 15

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2(x2-6x+9)-4(x-3) .... Report. 10/05/20 ... Since p(x) = 2x2 - 4x, we get: 4 - 4(x-3) = 4 - 4x + 12 = -8 - 4x (assuming 2x2 ... 4x. Note ** if in the original equation "2x2" means "2 times x to the power of 2" ... No packages or subscriptions, pay only for the time you need.2 answers Top answer:

p(x) = 2x2 – 4x and q(x) = x – 3, (p•q)(x).

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The value of h(10) if h(x) = 6 – X and (pºq)(x) are -4 and 2x² - 16x + 18 respectively

How to solve equation

h(x) = 6 – x

h(10) = 6 - 10

= -4

If

p(x) = 2x² - 4x

q(x) = x - 3

(pºq)(x)

= (2x² - 4x) (x - 3) × 4

= 2x² - 16x + 18

Learn more about equation:

https://brainly.com/question/2972832

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