Anayromero28idn
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If sin 0= 4/5 in quadrant II, what is cose? A. - 3/5 B. 3/5 C. - 3/4 D. 3/4

Sagot :

Answer:

A

Step-by-step explanation:

Given

sinθ = [tex]\frac{4}{5}[/tex] = [tex]\frac{opposite}{hypotenuse}[/tex]

This is a 3- 4- 5 triangle

with opposite = 4, adjacent = 3 and hypotenuse = 5

Since θ is in second quadrant then cosθ < 0

cosθ = [tex]\frac{adjacent}{hypotenuse}[/tex] = - [tex]\frac{3}{5}[/tex] → A

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