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A 4.0 Ohms resistor, an 8.0 Ohms resistor, and a 12.0 Ohms resistor are connected in series with a 24.0 V battery. Calculate the current in the circuit.

Sagot :

Answer:

RESISTANCE=(4+8+12)Ohms

=24 ohms

V=IR

24= I ×24

I= 24/24

I= 1 A

CURRENT IS 1 A

Answer:

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