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Answer:
The molarity will be "0.43 M" and molality will be "0.43 m".
Explanation:
Given that:
mass of NaCl,
= 25 g
Volume of solution,
= 1 L
Density of solution,
= 1 gm/cm³
Now,
The weight of solvent will be:
= [tex]Volume\times density[/tex]
= [tex]1\times 1[/tex]
= [tex]1 \ kg[/tex]
The mole of NaCl will be:
= [tex]\frac{mass}{Molar \ mass}[/tex]
= [tex]\frac{25}{58.44}[/tex]
= [tex]0.43[/tex]
hence,
The molarity will be:
= [tex]\frac{number \ of \ mole}{Volume \ of \ solution}[/tex]
= [tex]\frac{0.43}{1}[/tex]
= [tex]0.43 \ M[/tex]
The molality will be:
= [tex]\frac{mole \ of \ solute}{Weight \ of \ solvent}[/tex]
= [tex]\frac{0.43}{1}[/tex]
= [tex]0.43 \ m[/tex]