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Answer:
14.57%
Explanation:
From the previous lesson, we understood that the Volume of E.coli = 4.13 × 10⁻¹⁹ m³
The diameter of the ribosome = 20 nm
Radius will be D/2 = 20 nm/2 = 10 nm
The volume of the sphere since the shape of the ribosome is spherical = 4πr³
∴
The volume for each ribosome = 4πr³
For 15000 ribosome, we have:
[tex]= 15000 \times (\dfrac{4}{3}\pi) ((10^{-8})^3)[/tex]
[tex]= 15000 \times (\dfrac{4}{3}\pi) (10^{-24})[/tex]
= 6.283 × 10⁻²⁰
Thus, the fraction of E.coli volume occupied by the ribosome can be determined by using the formula:
[tex]= \dfrac{Vol. \ of \ ribosome}{Vol. \ of \ E.coli}\times 100[/tex]
[tex]= \dfrac{6.283 \times 10^{-20}}{4.31 \times 10^{-19}}\times 100[/tex]
= 14.57%