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Answer:
The program in Python is as follows:
nums = []
for i in range(3):
num = int(input(""))
nums.append(num)
print(min(nums))
Explanation:
This initializes a list of numbers
nums = []
This loop is repeated 3 times
for i in range(3):
For each repetition, this prompts the user for input
num = int(input(""))
This appends the input to the list
nums.append(num)
This gets the smallest of the three inputs using the min() function. The smallest is also printed
print(min(nums))
The Answer is in Bold:
#include <iostream>
using namespace std;
int main() {
int a, b, c; //NOTE: you don't have to put a, b, c. you can put it as x, y, z
//or you can make it as num1, num2, num3 etc.
cin >> a;
cin >> b;
cin >> c;
if (a < b && a < c) {
cout << a <<endl;
}
else if(b < a && b < c) {
cout << b << endl;
}
else {
cout << c <<endl;
}
return 0;
}