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Sagot :
Answer: The molarity of phosphoric acid is 0.05 M
Explanation:
A neutralization reaction is defined as the reaction in which an acid reacts with a base to form a salt and water molecule.
At equivalence, moles of acid becomes equal to the moles of base. The equation for the neutralization follows:
[tex]n_1M_1V_1=n_2M_2V_2[/tex] ........(1)
where,
[tex]n_1, M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid that is [tex]H_3PO_4[/tex]
[tex]n_2, M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of the base that is NaOH
Given values:
[tex]n_1=3\\M_1=?M\\V_1=10.00mL\\n_2=1\\M_2=0.1000M\\V_2=15.00mL[/tex]
Plugging values in equation 1:
[tex]3\times M_1\times 10.00=1\times 0.1000\times 15.00\\\\M_1=\frac{1\times 0.1000\times 15.00}{3\times 10.00}\\\\M_1=0.05M[/tex]
Hence, the molarity of phosphoric acid is 0.05 M
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