Answered

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If 16x2 + nx + 49 is the square of a
binomial, then what value could n be?
A.14
B.28
C.42
D.56

Sagot :

Answer:

Th correct option is (d).

Step-by-step explanation:

The given expression is :

[tex]16x^2 + nx + 49[/tex] ....(1)

We know that, 16 = 4² and 49 = 7²

Also, (a+b)² = a²+2ab+b²

The given expression becomes,

[tex]16x^2 + nx + 49=(4x)^2+nx+7^2\\\\=(4x)^2+2(4x)(7)+7^2\\\\=16x^2+56x+49\ ......(2)[/tex]

Comparing equations (1) and (2),

n = 56

Hence, the value of n is equal to 56.

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