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Find the zeros of the quadratic function: y= 6(7x + 9)(8x - 3).
A) (-9/7,0), (3/8,0)
B)(-7/9,0), (8/3,0)
C) (-3/8,0), (°/7,0)
D) (-8/3,0), (7/9,0)

Sagot :

Answer:

A) (-9/7,0), (3/8,0)

Step-by-step explanation:

Zeros of a quadratic function:

x for which y = 0.

In this question:

[tex]y = 6(7x + 9)(8x - 3)[/tex]

It's 0 if one of the factors is 0. 6 is never 0, now about the other to:

[tex]7x + 9 = 0[/tex]

[tex]7x = -9[/tex]

[tex]x = -\frac{9}{7}[/tex]

So (-9/7, 0) is a zero of the quadratic function.

The other is:

[tex]8x - 3 = 0[/tex]

[tex]8x = 3[/tex]

[tex]x = \frac{3}{8}[/tex]

(3/8,0) is the other zero.

Thus, the correct answer is given by option A.

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