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Sagot :

Given:

A figure of a right angle triangle.

To find:

The length of BC.

Solution:

In a right angle triangle,

[tex]\tan \theta =\dfrac{Perpendicular}{Base}[/tex]

In the given triangle,

[tex]\tan A =\dfrac{BC}{AC}[/tex]

[tex]\tan 23^\circ =\dfrac{BC}{6}[/tex]

[tex]0.42447\times 6 =BC[/tex]

[tex]2.54682 =BC[/tex]

Approximate the value to the nearest hundredth.

[tex]BC\approx 2.55[/tex]

Therefore, the measure of side BC is 2.55 units.