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Sagot :
To Find :
Gas’s temperature in Celsius when it has a volume of 25 L, 203 mol, 143.5 atm .
Solution :
We know, by ideal gas equation :
[tex]PV =nRT\\\\T = \dfrac{PV}{nR}[/tex]
Here, R is universal gas constant and [tex]R = 0.082 \ L \ atm \ mol^{-1} \ K^{1}[/tex]
Putting all given values and R in above equation, we get :
[tex]T = \dfrac{PV}{nR}\\\\T = \dfrac{143.5\times 25}{203 \times 0.082}\ K\\\\T = 215.52\ K[/tex]
Hence, this is the required solution.
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