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Sagot :
[tex]\huge\bold{Question}[/tex]
Prove that [tex]\sqrt{n} [/tex] is not a rational number, if n is not perfect square.
[tex]\huge{\underline{\underline{\mathrm{\red{AnswEr}}}}}[/tex] [tex]\huge\bold\blue{=}[/tex]
[tex]\sqrt{4} [/tex]= 2 where 2 is a rational number . Here n is perfect square the [tex]\sqrt{n} [/tex] is rational number
[tex]\sqrt{5} [/tex] = 2.236.. is not rational number But it is irrational number.here n is not a perfect square the [tex]\sqrt{n} [/tex] is irrational number
So [tex]\sqrt{n} [/tex] is not irrational number if n is perfect square.
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