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A peanut was burned in a calorimeter filled with 70g of water. The temperature
increased from 21°C to 87°C. How much heat was released by the peanut. The
specific heat of water is 4.18 J/gºC *

Sagot :

Answer:

[tex]heat = mc \triangle \theta \\ = 70 \times 4.18 \times (87 - 21) \\ = 19311.6 \: joules[/tex]

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