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Sagot :
Answer: The molar mass of protein A is 3023.41 g/mol.
Explanation:
To calculate the osmotic pressure, we use the formula:
[tex]\pi=i\times M\times R\times T[/tex]
OR
[tex]\pi=i\times \frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution}}\times R\times T[/tex] .....(1)
Where,
[tex]\pi[/tex] = osmotic pressure = 0.285 atm
i = 1
Given mass of protien (solute) = 54.1 mg = 0.0541 g (Conversion factor: 1 g = 1000 mg)
Volume of solution = 1.5 mL
R = Gas constant = 0.0821 L.atm/mol.K
T = temperature = [tex]18^oC=[18+273]=291K[/tex]
Plugging values in equation 1:
[tex]0.285atm=1\times \frac{0.0541\times 1000}{\text{Molar mass of protein}\times 1.5}\times 0.0821L.atm/mol.K\times 291K\\\\\text{Molar mass of protein}=\frac{1\times 0.0541\times 1000\times 0.0821\times 291}{0.285\times 1.5}\\\\\text{Molar mass of protein}=3023.41g/mol[/tex]
Hence, the molar mass of protein A is 3023.41 g/mol.
The molar mass of the protein is 3018 g/mol.
We know that the osmotic pressure is obtained using the formula;
Osmotic pressure = iMRT
- i = Van't Hoff factor
- M = molar concentration
- R = gas constant
- T = absolute temperature
concentration of the protein = 54.1 * 10^-3g/M/ 1.5 * 10^-3 L
Where M = molar mass of the protein
So;
0.285 atm = 54.1 * 10^-3g/ 1.5 * 10^-3 L M * 0.0821 L.atm/mol.K * 291 K
0.285 = 1.29/1.5 * 10^-3M
M = 1.29/0.285 * 1.5 * 10^-3
M = 3018 g/mol
Learn more about osmotic pressure: https://brainly.com/question/4631715
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