Answered

Ask questions, share knowledge, and connect with a vibrant community on IDNLearn.com. Whether it's a simple query or a complex problem, our community has the answers you need.

Find all angles, o<Θ<360, that satisfy the equation below, to the nearest 10th of a degree.

4cos^2Θ-2=-1

Find All Angles OltΘlt360 That Satisfy The Equation Below To The Nearest 10th Of A Degree 4cos2Θ21 class=

Sagot :

Facundo3141592idn

Answer:

30° and 150°

Step-by-step explanation:

We want to find the angles in the range:

0° < θ < 360°

Such that:

4*cos^2(θ) - 2 = 1

The first part is to isolate the variable θ in one side of the equation, let's do that:

4*cos^2(θ) = 1 + 2 = 3

cos^2(θ) = 3/4

cos(θ) = ± √(3/4) = ± (√3)/2

Then we have two possible values of θ, one for:

cos(θ) =  (√3)/2

And another for

cos(θ) = - (√3)/2

For both cases, we can use the inverse cosine function, Acos(x)

that has the property Acos( cos(x) ) = x

Then:

cos(θ) =  (√3)/2

Acos( cos(θ) ) = Acos(  (√3)/2)

θ = Acos(  (√3)/2) = 30°

And for the other case we have:

θ = Acos( - (√3)/2) = 150°

Then the two values of theta are: 30° and 150°

(We can see that both of these values are in the range 0° < θ < 360°)

We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. For precise answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.