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Sagot :
Answer:
The correct answer is 1.498.
Explanation:
Based on the given information, the volume of NaOH needed for the titration is 14.53 ml, and the concentration of NaOH given is 0.1031 M.
The volume of NaOH, that is, 14.53 ml can also be written as 14.53 × 10⁻³ L.
The concentration of NaOH, that is, 0.1031 M can also be written as 0.1031 moles/Litre.
Molarity (M) is determined as,
M = No of moles/Volume in litres
No of moles = Molarity × Litres
No of moles = 0.1031 moles/Litres × 14.53 × 10⁻³ L
No of moles = 1.498 × 10⁻³ L
Now, number of millimoles = 1.498 × 10⁻³ L × 1000 (millimoles = moles × 1000)
Number of millimoles = 1.498
The number of millimoles of NaOH required for the titration is 1.50 mmol
From the question,
We are to determine the number of millimoles of NaOH required for the titration
From the given information
The titration required 14.53 mL of 0.1031 M NaOH solution
From the formula
Number of moles = Concentration × Volume
Concentration of the NaOH = 0.1031 M
Volume of the NaOH = 14.53 mL
∴ Number of millimoles of NaOH required = 0.1031 × 14.53
Number of millimoles of NaOH required = 1.498043 mmol
Number of millimoles of NaOH required ≅ 1.50 mmol
Hence, the number of millimoles of NaOH required for the titration is 1.50 mmol
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