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Sagot :
Answer:
Step-by-step explanation:
Hooke's Law applies here, which is a linear relationship. It would be easier to solve this using proportions with N of force on the top and the amount of stretch in cm on the bottom. Set up with our unknown, the number of cm:
[tex]\frac{N}{cm}:\frac{20}{5}=\frac{60}{x}[/tex] and cross multiply:
20x = 300 so
x = 15 cm
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