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Use trigonometric ratios to solve the right triangle.

Use Trigonometric Ratios To Solve The Right Triangle class=

Sagot :

Answer:

[tex]DF=15, DE=5\sqrt{3}[/tex]

Step-by-step explanation:

[tex]sin(60)=\frac{DF}{EF} =\frac{DF}{10\sqrt{3} }\\DF=10\sqrt{3} sin(60)=10\sqrt{3} \times \frac{\sqrt{3} }{2} =15\\cos(60)=\frac{DE}{EF} =\frac{DE}{10\sqrt{3} }\\DE=10\sqrt{3} cos(60)=10\sqrt{3} \times \frac{1 }{2} =5\sqrt{3}[/tex]

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