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The specific heat capacity of water is 4.186 J/g °C
Calculate the temperature change when 8000 J of heat is added to 3g of water.
Use the equation q=mcT

The Specific Heat Capacity Of Water Is 4186 Jg C Calculate The Temperature Change When 8000 J Of Heat Is Added To 3g Of Water Use The Equation QmcT class=

Sagot :

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Answer:

Q

C= M×∆T

Explanation:

Energy (Q) J

Change of temperature (ΔT) °C

Mass (m) kg

Substance (optional) Custom ▾

Specific heat capacity (c) J/(kg·K)

HOPE IT HELPS

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Answer:

Solution given:

specific heat capacity of water [c]4.186 J/g °C

temperature[∆T]=?

mass[m]=3g

heat[Q]=8000J

we have

Q=mc∆T

8000=3*4.186*∆T

∆T=8000/12.558

∆T=637.04°C

the temperature change is 637.04°C.

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