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Sagot :
English Translation :
A gas at a temperature of 38 °C, have a volume of 21 Lts Liters. What volume will it have if the temperature rises to 67°C?
Solution :
Since, there is no information about pressure, let us assume it is constant.
So, by ideal gas equation at constant pressure :
[tex]V_1 T_2 = V_2 T_1[/tex]
Putting given volume and temperature ( in Kelvin ) in above equation, we get :
[tex]21 \times ( 67 + 273 ) = V_2 \times ( 38 + 273 )\\\\V_2 = \dfrac{21 \times (67+273) }{(38+273)}\\\\V_2 = 22.96 \ L[/tex]
Hence, this is the required solution.
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