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1. “Systems of Linear Equations”
American Airlines sold a certain number of tickets from Los Angeles to Hawaii. They charged $90
for flight x and the remaining tickets for $250 for flight y. If the airline sold 120 tickets and
collected a total of $27,600 from the sale of those tickets:
a) Set up the System of Linear Equations
b) How many tickets of each flight were sold?
c) How much money was made from each flight?

1 Systems Of Linear Equations American Airlines Sold A Certain Number Of Tickets From Los Angeles To Hawaii They Charged 90 For Flight X And The Remaining Ticke class=

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Answer:

Part A)

[tex]\begin{aligned} x+y&=120 \\ 90x+250y&=27600\end{aligned}[/tex]

Part B)

Flight X sold 15 tickets and Flight Y sold 105 tickets.

Part C)

Flight X made $1,350 and Flight Y made $26,250.

Step-by-step explanation:

Let the amount of tickets sold by Flight X be represented by x and the amount of tickets sold by Flight Y be represented by y.

Part A)

The airline sold 120 tickets in total. Hence:

[tex]x+y=120[/tex]

Each x ticket costs $90 and each y ticket costs 250. The total income was $27,600. Thus:

[tex]90x+250y=27600[/tex]

Our system of equations is:

[tex]\begin{aligned} x+y&=120 \\ 90x+250y&=27600\end{aligned}[/tex]

Part B)

Solve the system of equations. We can use substitution. From the first equation, subtract y from both sides:

[tex]x=120-y[/tex]

In the second equation, we can divide everything by 10 and substitute in x:

[tex]9(120-y)+25y=2760[/tex]

Simplify:

[tex]16y+1080=2760[/tex]

So:

[tex]y=105\text{ tickets}[/tex]

Using the equation above:

[tex]x=120-(105)=15\text{ tickets}[/tex]

Flight X sold 15 tickets and Flight Y sold 105 tickets.

Part C)

Since each ticket of Flight X sold for $90 and Flight X sold 15 tickets, Flight X made $1,350.

Then it follows that Flight Y made $26,250.

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