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2.
A charge particle is moved through a potential difference of 154.5 V and experiences a
change of electric potential energy of 4.26 x 10-8 J. What is the charge of the particle?

Sagot :

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Answer:

2.76×10⁻¹⁰ C

Explanation:

Applying,

V = W/q................... Equation 1

Where V = Electric Potential, E = Electric potential energy, q = charge.

make q the subject of the equation

q = W/V................ Equation 2

From the question,

Given: W = 4.26×10⁻⁸ J, V = 154.5 V

Substitute these values into equation 2

q = 4.26×10⁻⁸/154.5

q = 2.76×10⁻¹⁰ C

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