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A pair of oppositely charged plates is separated by 0.09 m. A potential difference of
285 V exists between the plates. What is the electric field that exists between the plates?

Sagot :

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Answer:

25.65 V/m

Explanation:

Applying,

V = Er................. Equation 1

Where V = Electric potential, E = electric field, r = distance of seperation.

make E the subject of the equation

E = V/r.............. Equation 2

From the question,

Given: V = 285 V, r = 0.09 m

Substitute these values into equation 2

E = (285×0.09)

E = 25.65 V/m

Hence the electric field between the plates is 25.65 V/m