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3. Automobile companies often test the safety of cars by putting them through crash tests to observe the integrity of the passenger compartment. If 1100kg car is sent toward a cement wall with a speed of15 m/s, an impact force of 185,000 N stops the car, how long does it take before the car is brought to a stop?​

Sagot :

Answer:

Time taken for car to stop = 0.89 seconds (Approx.)

Explanation:

Given:

Mass of car = 1100 kg

Speed of car = 15 m/s

Impact force = 185,000 N

Find:

Time taken for car to stop

Computation:

Change in momentum of car = M(v) - M(u)

Change in momentum of car = 1100(0) - 1100(15)

Change in momentum of car = -16,500

Time taken for car to stop = I Change in momentum of car I / Impact force

Time taken for car to stop = I-16,500I / 185,000

Time taken for car to stop = 0.89 seconds (Approx.)

The time it takes for the car to stop will be 0.89 sec. Due to the external resistive force, the car will stop after some time.

What is momentum?

The momentum is defined as the product of mass and the velocity of the body. It is denoted by the letter P. It occurs due to the applied force. Its unit is Kg m/s².

The change in the momentum of the car is given as;

[tex]\rm \triangle P = m(V-U) \\\\ \triangle P = 1100(0-5) \\\\ \rm \triangle P =-16,500 Kgm/s[/tex]

The time taken for a car to stop will be;

[tex]I \triangle p= F\triangle t \\\\ \rm t = \frac{\triangle p }{F} \\\\ \rm t = \frac{|-16500|}{18500} \\\\ \rm t =0.89 \ sec[/tex]

Hence the time it takes for the car to stop is 0.89 sec.

To learn more about the momentum refer to the link;

https://brainly.com/question/4956182

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