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How fast was a driver going if it left skid marks that were 63 feet long on wet concrete? (The
coefficient of friction is 0.97)?
O 61 mph
31 mph
O 334 mph
43 mph

Sagot :

Nukanukanukaidn
The answer would be A 61

The required speed of the driver is 33.4 mph.

To determine how fast was a driver going and if it left skid marks that were 63 feet long on wet concrete. (The coefficient of friction is 0.97)?

What is speed?

Speed is the ratio of distance traveled to time taken to travel that distance.

What is friction?

Friction is defined as resistance force from one surface to the other between two solid materials caused by reciprocal movement is called friction. And the force applied is called friction force.

Since from given
f = 0.97
left skid marks that were 63 feet long on wet concrete.
d = 63 feets
g = 9.8

V = √( 2g * F * D )
V = √(2 * 9.8 * 0.97 * 63 )
V = 33.4mph

Thus, The required speed of the driver is 33.4 mph.

Learn more about speed here:
https://brainly.com/question/7359669

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