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Trancescientidn

13. $25/month

14. 36 and 37

Step-by-step explanation:

Let a = monthly rate ($/month)

t = time (months)

k = installation cost

The equation for the cost of the internet service C is

C = at + k

Since C = $685. t = 24 months (2 years) and k = $85, we can solve for a:

at = C - k

or

a = (C - k)/t

= ($685 - $85)/(24 months)

= $25/month

14. Let n = the number

n + 1 = the number after n

Since the sum of two consecutive numbers is 73, we can write the equation as

n + (n + 1) = 73

which simplifies to

2n + 1 = 73

2n = 72

Solving for n, we find that

n = 36

so the other number is 36 + 1 = 37.

Tan2vyidn

Answer For The First Question:

25

Here's why:

Note that the cost corresponds to 2 years of service.  Also, the problem asks for the one-month fee.  Then, a good start would be saying: OK, the cost of 24 months of service was $685, including the installation fee. Since this fee is a one-time cost, not a monthly cost, we need to subtract it from our total cost. Then the cost of the service minus the installation fee could be written as:

24x = 685 - 85

That is 24 months of service, at x cost per month, is equal to 685 minus 85.  

 If you solve this equation, you will find the value of x:

24x = 600  

 x = 600 ÷ 24

 x = 25

The monthly fee is $25. In 2 years you paid 24 times 25, or $600.  Add to this amount the installation fee of $85 and you will arrive at your total cost, which includes the installation fee.

Second Answer:

36 and 37

Here's why:

36+37=73

You can solve this by first dividing 73 by 2.

73/2 = 36.5

Next, take .5 away from one of the 36.5 and give it to the other one. That gives us an answer of 36 and 37.

I hope this helps! If you are confused about anything, let me know :)

 

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