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How do I solve this. Please help!!

How Do I Solve This Please Help class=

Sagot :

Answer:

x = 4[tex]\sqrt{2}[/tex]

Step-by-step explanation:

Using the sine ratio in the right triangle and the exact value

sin45° = [tex]\frac{1}{\sqrt{2} }[/tex] , then using the upper 45°

sin45° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{4}{x}[/tex] = [tex]\frac{1}{\sqrt{2} }[/tex] ( cross- multiply )

x = 4[tex]\sqrt{2}[/tex]

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